Equation of a straight line is Y=mx c Now , for your equation Y=X1X2 or Y= 2X3 so equating it with the equation of a straight line , m=2 & c=3 Hence, the graph will be a straight line for this equation Start putting X value from zero & plot the Y values and you will get the Coordinates of X,Y which will determine the straight line graphSteps to graph x^2 y^2 = 4Subtracting x 2 from itself leaves 0 \left (y\sqrt 3 {x}\right)^ {2}=1x^ {2} ( y 3 x ) 2 = 1 − x 2 Take the square root of both sides of the equation Take the square root of both sides of the equation y\sqrt 3 {x}=\sqrt {1x^ {2}} y\sqrt 3 {x}=\sqrt {1x^
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Y x 1/x^2 graph-Example Use transformations to graph f(x) = 3x 2 Start with a basic function and use one transformation at a time Show all intermediate graphs This function is obtained from the graph of y = 3x by first reflecting it about yaxis (obtaining y = So y is always positive As x becomes smaller and smaller then 1/(1x^2) > 1/1 = 1 So lim_(x>0) 1/(1x^2)=1 As x becomes bigger and bigger then 1x^2 becomes bigger so 1/(1x^2) becomes smaller lim_(x>oo) 1/(1x^2)=0 color(blue)("build a table of value for different values of "x" and calculate the appropriate values of y
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X^{2}x=y1 Subtract 1 from both sides x^{2}x\left(\frac{1}{2}\right)^{2}=y1\left(\frac{1}{2}\right)^{2} Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2} Then add the square of \frac{1}{2} to both sides of the equation This step makes the left hand side of the equation a perfect squareGraph of y = x 1Slope = 1Gradiant = Rise/Run = 1/1 = 1 (Run is always 1)We have a line with slope of 1 and intercepts the yaxis at 1 with two points we//googl/JQ8NysThe Graphs of y = 1/x and y = 1/x^2 College Algebra
Unlock StepbyStep plot x^2y^2x Natural Language Math Input NEW Use textbook math notation to enter your math Try it × Extended Keyboard ExamplesWe will use 1 and 4 for x If x = 1, y = 2(1) 6 = 4 if x = 4, y = 2(4) 6 = 2 Thus, two solutions of the equation are (1, 4) and (4, 2) Next, we graph these ordered pairs and draw a straight line through the points as shown in the figure We use arrowheads to show that the line extends infinitely far in both directionsMath Input NEW Use textbook math notation to enter your math Try it
This answer is not useful Show activity on this post In Mathematica tongue x^2 y^2 = 1 is pronounced as x^2 y^2 == 1 x^2y^2=1 It is a hyperbola, WolframAlpha is verry helpfull for first findings, The Documentation Center (hit F1) is helpfull as well, see Function Visualization, Plot3D x^2 y^2 == 1, {x, 5, 5}, {y, 5, 5}Given that both equations are true at the same time and obviously x = x, y 1 = 2 y − 2 so y = 3, and x = 4 The point ( 4, 3) graphically is the intersection of the two lines When two linear equations in two variables are simultaneously satisfied, the pair is understan Continue ReadingGraph the parabola, y =x^21 by finding the turning point and using a table to find values for x and y
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1plot x^2 2invert it about x axis 3raise it upwards by 1 unit 4This is y=1x^2 5for mod (y), along with this, take mirror image about x axis 6Combined graph is the solution 7Restrict answer between y=1 and y=1 as maximum value of mod (y) is 1 41K viewsSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreDemonstration of how to graph an equation in slope intercept form interpreting the slope at the coefficient of x and the constant term as the yinterceptSlo
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyThe graph of y=1/x^2 is a visual presentation of the function in the plane On the given graph you can find all of the important points for function y=1/x^2 (if they exist)This takes the graph of y = x^2 and moves each point 2 to the left y=(x3)^2 This takes the graph of y = x^2 and moves each point 3 to the left===== Cheers, Stan H Answer by jojo(1513) (Show Source) You can put this solution on YOUR website!
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Observe that as y = 1 − 1 (1 x)2, value of y or range of x2 1 x2 is limited between 0,1) Further, as dy dx = 0 only at x = 0 and x = ± ∞ and hence we have an extrema at these points Now for second derivative using quotient formula, it isBased on the definition of vertical shrink, the graph of y 1 (x) should look like the graph of f (x), vertically shrunk by a factor of 1/2 Take a look at the graphs of f (x) and y 1 (x) Notice that the xintercepts have not moved Function (2), g (x), is a sine function What would the graph ofFind stepbystep Discrete math solutions and your answer to the following textbook question Construct a precedence graph for the following program S₁ x = 0
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Y = 2 1 y = 1 So your first point has coordinates of (2, 1) Now repeat this operation with a different value of x, say x = 5 y = 5 1 y = 4 Your second point has coordinates (5, 4) Now mark these two locations on your graph paper Starting at the origin of your graph (where the xaxis crosses the yaxis), go to the right 2 squares (x=2See the vertex on each "y" function below, it moves an increment of 1 from 0 of the xThe coefficient of \(x^3\) is positive, so for large \(x\) we get a positive \(y\), in which case (a) cannot be the graph When \(x=0\), \(y=1\), so the \(y\)intercept is \(1\) and therefore (b) cannot be the graph
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A sketch of the graph \(y=x^3x^2x1\) appears on which of the following axes?Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more The #x^2# is positive so the general graph shape is #uu# Consider the generalised form of #y=ax^2bxc# The #bx# part of the equation shifts the graph left or right You do not have any #bx# type of value in your equation So the graph is central about the yaxis The #c# part of the equation is of value 1 so it lifts the vertex up from y=0
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How to plot y=1/x as a single graph duplicate Ask Question Asked 4 years, 6 months ago Active 4 years, 6 months ago (ex y=1/(x2)) Thank you all for contributions python numpy matplotlib plot Share Follow edited May 18 '17 at 946 Tim GO asked May 18 '17 at 714 Tim GO Tim GO 131 1 1 gold badge 1 1 silver badge 6 6 bronzeY=x^21 (Graph Example), 4x2=2 (x6) (Solve Example) Algebra Calculator is a calculator that gives stepbystep help on algebra problems See More Examples » x3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank youCos(x^2) (x−3)(x3) Zooming and Recentering You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original click on the Reset button Using "a" Values
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Graph x^2y^2=1 x2 y2 = 1 x 2 y 2 = 1 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h represents the xoffset from the origin, and k k represents the yoffset from originGraph y=(x1)(x2) Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for The focus of a parabola can be found by adding to the ycoordinate if the parabola opens upPlot sqrt(1 x y), sqrt(x^2 y^2 2 x y) Natural Language;
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Graph y= (x1)^22 y = (x − 1)2 2 y = ( x 1) 2 2 Find the properties of the given parabola Tap for more steps Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 h = 1 h = 1 k = 2 k = 2Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicBeyond simple math and grouping (like "(x2)(x4)"), there are some functions you can use as well Look below to see them all They are mostly standard functions written as you might expect You can also use "pi" and "e" as their respective constants Please
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Please Subscribe here, thank you!!!Answer (1 of 3) Graph of y=x is the straight line crossing from the origin and will go in first and 3rd quadrant And graph of y=x is also straight line but due to negative, it would start from the origin and will go to the 2nd and 4th quadrant, y=x1 graph would go one unit up from its curre1x b 0 The graph of y = f(x) will have vertical asymptotes at those values of x for which the denominator is equal to zero The graph of y = f(x) will have at most one horizontal asymptote It is found according to the following 1 If m > n (that is, the degree of
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Here 1 is subtracted from x, so we have to shift the graph of y = x 2, 1 unit to the right side Step 3 The positive number 3 is multiplied by (x1) which is greater than 1, so we have to compress the curve y = (x1) 2 towards yaxisAlgebra Graph y=x^ (1/2) y = x1 2 y = x 1 2 Graph y = x1 2 y = x 1 2Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance
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So the curve passes through (0, 1) Here is the graph of y = (x − 1) 2 Example 5 y = (x 2) 2 With similar reasoning to the last example, I know that my curve is going to be completely above the xaxis, except at x = −2 The "plus 2" in brackets has the effect of moving our parabola 2 units to the left Rotating the ParabolaGraphing Linear Inequalities This is a graph of a linear inequality The inequality y ≤ x 2 You can see the y = x 2 line, and the shaded area is where y is less than or equal to x 2Use "x" as the variable like this Examples sin(x) 2x−3;
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Here is a picture of the graph of g(x) = 3(x)1/2 Since c = 3 > 1, the graph is obtained from that of f(x) = x1/2 by stretching it in the ydirection by a factor of c = 3 Reflection about the x axis The graph of y = f (x) is the graph of y = f (x) reflected about the x axis Here is a picture of the graph of g(x) = (x 2 1) It is obtainedFirst, you probably mean y=(1x)/(1x) The way you have it written, that would be y=1xx, ie, y=1, or a straight horizontal line Anyway, your intended graph is a hyperbola, which you can see by expressing it as y = 2/(x1) 1 The "1" shifts y=1/x one way, the "2" elongates it a bit, and the "1" shifts it againDivide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square
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Graph y=1/2x2 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is , where is the slope and is the yintercept Write in form To find the xintercept (s), substitute in for and solve for Solve the equation Tap for more steps Rewrite the equation as
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